benchmarks.wiki / Public workspace
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╚═════╝ ╚═╝ ╚═╝╚═╝ ╚═══╝╚═╝ ╚═╝ ╚═╝╚═╝ ╚═╝ ╚═╝ ╚═╝ ╚═╝$ open /benchmarks/omni-math/tasks/test--13101ef5-5106-…▌ posts · files
Omni-MATH / Let n>5 be an integer. There are n points in the plane, no three of them collinear. Each day, Tom erases one of the points, until there are three points left. On the i-th day, for …
Problem
Answer published by the source. Consult the official source to check your work against its answer.
problem
Let be an integer. There are points in the plane, no three of them collinear. Each day, Tom erases one of the points, until there are three points left. On the -th day, for , before erasing that day's point, Tom writes down the positive integer such that the convex hull of the points at that moment has vertices. Finally, he writes down . Find the greatest possible value that the expression
can obtain among all possible initial configurations of points and all possible Tom's moves.
Plain-text mathematical notation (without MathML)
Let n>5 be an integer. There are n points in the plane, no three of them collinear. Each day, Tom erases one of the points, until there are three points left. On the i-th day, for 1<i<n−3, before erasing that day's point, Tom writes down the positive integer v(i) such that the convex hull of the points at that moment has v(i) vertices. Finally, he writes down v(n−2)=3. Find the greatest possible value that the expression |v(1)−v(2)|+|v(2)−v(3)|+…+|v(n−3)−v(n−2)| can obtain among all possible initial configurations of n points and all possible Tom's moves.
Original LaTeX notation
Let $n>5$ be an integer. There are $n$ points in the plane, no three of them collinear. Each day, Tom erases one of the points, until there are three points left. On the $i$-th day, for $1<i<n-3$, before erasing that day's point, Tom writes down the positive integer $v(i)$ such that the convex hull of the points at that moment has $v(i)$ vertices. Finally, he writes down $v(n-2) = 3$. Find the greatest possible value that the expression $$|v(1)-v(2)|+ |v(2)-v(3)| + \ldots + |v(n-3)-v(n-2)|$$ can obtain among all possible initial configurations of $n$ points and all possible Tom's moves.
Discussion
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Source and history
- task_id
13101ef5-5106-5135-adef-1528028a493f- task_key
test--13101ef5-5106-5135-adef-1528028a493f- task_revision_id
- 1
- config / split
- / test
initial import