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Omni-MATH / A polynomial P of degree 2015 satisfies the equation P(n)=(1)/(n²) for n=1,2,…,2016. Find …

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problem

A polynomial PP of degree 2015 satisfies the equation P(n)=1n2P(n)=\frac{1}{n^{2}} for n=1,2,…,2016n=1,2, \ldots, 2016. Find \lfloor 2017 P(2017)\rfloor.
Plain-text mathematical notation (without MathML)
A polynomial P of degree 2015 satisfies the equation P(n)=(1)/(n²) for n=1,2,…,2016. Find \lfloor 2017 P(2017)\rfloor.
Original LaTeX notation
A polynomial $P$ of degree 2015 satisfies the equation $P(n)=\frac{1}{n^{2}}$ for $n=1,2, \ldots, 2016$. Find \lfloor 2017 P(2017)\rfloor.

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