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Omni-MATH / The triangle ABC is isosceles with AB=AC, and ∠BAC<60^(∘). The points D and E are chosen on the side AC such that, EB=ED, and ∠ABD≡∠CBE. Denote by O the intersection point between …

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The triangle ABCABC is isosceles with AB=ACAB=AC, and ∠BAC<60∘\angle{BAC}<60^{\circ}. The points DD and EE are chosen on the side ACAC such that, EB=EDEB=ED, and ∠ABD≡∠CBE\angle{ABD}\equiv\angle{CBE}. Denote by OO the intersection point between the internal bisectors of the angles ∠BDC\angle{BDC} and ∠ACB\angle{ACB}. Compute ∠COD\angle{COD}.
Plain-text mathematical notation (without MathML)
The triangle ABC is isosceles with AB=AC, and ∠BAC<60^(∘). The points D and E are chosen on the side AC such that, EB=ED, and ∠ABD≡∠CBE. Denote by O the intersection point between the internal bisectors of the angles ∠BDC and ∠ACB. Compute ∠COD.
Original LaTeX notation
The triangle $ABC$ is isosceles with $AB=AC$, and $\angle{BAC}<60^{\circ}$. The points $D$ and $E$ are chosen on the side $AC$ such that, $EB=ED$, and $\angle{ABD}\equiv\angle{CBE}$. Denote by $O$ the intersection point between the internal bisectors of the angles $\angle{BDC}$ and $\angle{ACB}$. Compute $\angle{COD}$.

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