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Omni-MATH / Find the number of ordered triples of divisors (d₁,d₂,d₃) of 360 such that d₁d₂d₃ is also a divisor of 360.

Problem

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problem

Find the number of ordered triples of divisors (d1,d2,d3)(d_{1}, d_{2}, d_{3}) of 360 such that d1d2d3d_{1} d_{2} d_{3} is also a divisor of 360.
Plain-text mathematical notation (without MathML)
Find the number of ordered triples of divisors (d₁,d₂,d₃) of 360 such that d₁d₂d₃ is also a divisor of 360.
Original LaTeX notation
Find the number of ordered triples of divisors $(d_{1}, d_{2}, d_{3})$ of 360 such that $d_{1} d_{2} d_{3}$ is also a divisor of 360.

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