benchmarks.wiki / Public workspace

Omni-MATH / A sequence (a_(n)) of real numbers is defined by a₀=1, a₁=2015 and for all n≥1, we have a_(n+1)=(n−1)/(n+1)a_(n)−(n−2)/(n²+n)a_(n−1). Calculate the value of …

Problem

Answer published by the source. Consult the official source to check your work against its answer.

problem

A sequence (an)(a_n) of real numbers is defined by a0=1a_0=1, a1=2015a_1=2015 and for all n≥1n\geq1, we have an+1=n−1n+1an−n−2n2+nan−1.a_{n+1}=\frac{n-1}{n+1}a_n-\frac{n-2}{n^2+n}a_{n-1}. Calculate the value of a1a2−a2a3+a3a4−a4a5+…+a2013a2014−a2014a2015\frac{a_1}{a_2}-\frac{a_2}{a_3}+\frac{a_3}{a_4}-\frac{a_4}{a_5}+\ldots+\frac{a_{2013}}{a_{2014}}-\frac{a_{2014}}{a_{2015}}.
Plain-text mathematical notation (without MathML)
A sequence (a_(n)) of real numbers is defined by a₀=1, a₁=2015 and for all n≥1, we have
a_(n+1)=(n−1)/(n+1)a_(n)−(n−2)/(n²+n)a_(n−1).
Calculate the value of (a₁)/(a₂)−(a₂)/(a₃)+(a₃)/(a₄)−(a₄)/(a₅)+…+(a₂₀₁₃)/(a₂₀₁₄)−(a₂₀₁₄)/(a₂₀₁₅).
Original LaTeX notation
A sequence $(a_n)$ of real numbers is defined by $a_0=1$, $a_1=2015$ and for all $n\geq1$, we have
$$a_{n+1}=\frac{n-1}{n+1}a_n-\frac{n-2}{n^2+n}a_{n-1}.$$
Calculate the value of $\frac{a_1}{a_2}-\frac{a_2}{a_3}+\frac{a_3}{a_4}-\frac{a_4}{a_5}+\ldots+\frac{a_{2013}}{a_{2014}}-\frac{a_{2014}}{a_{2015}}$.

Discussion

Discussion

No discussion posts on this page yet. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

Source and history

Official source

initial import