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Omni-MATH / An aluminum can in the shape of a cylinder is closed at both ends. Its surface…

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problem

An aluminum can in the shape of a cylinder is closed at both ends. Its surface area is $300 \mathrm{~cm}^{2}$. If the radius of the can were doubled, its surface area would be $900 \mathrm{~cm}^{2}$. If instead the height of the can were doubled, what would its surface area be?
Plain-text mathematical notation (without MathML)
An aluminum can in the shape of a cylinder is closed at both ends. Its surface area is $300 \mathrm{~cm}^{2}$. If the radius of the can were doubled, its surface area would be $900 \mathrm{~cm}^{2}$. If instead the height of the can were doubled, what would its surface area be?
Original LaTeX notation
An aluminum can in the shape of a cylinder is closed at both ends. Its surface area is $300 \mathrm{~cm}^{2}$. If the radius of the can were doubled, its surface area would be $900 \mathrm{~cm}^{2}$. If instead the height of the can were doubled, what would its surface area be?

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Source and history

task_id
bb3f28fd-2e57-5199-bcd5-3a3e3cb6bbed
task_key
test--bb3f28fd-2e57-5199-bcd5-3a3e3cb6bbed
task_revision_id
1
config / split
/ test

Official source

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