benchmarks.wiki / Public workspace

Omni-MATH / A sequence (a_(n))_(n=1)^(∞) of positive integers satisfies the condition a_(n+1)=a_(n)+τ(n) for all positive integers n where τ(n) is the number of positive integer divisors of n.…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

problem

A sequence (an)n=1∞(a_n)_{n=1}^{\infty} of positive integers satisfies the condition an+1=an+τ(n)a_{n+1} = a_n +\tau (n) for all positive integers nn where τ(n)\tau (n) is the number of positive integer divisors of nn. Determine whether two consecutive terms of this sequence can be perfect squares.
Plain-text mathematical notation (without MathML)
A sequence (a_(n))_(n=1)^(∞) of positive integers satisfies the condition a_(n+1)=a_(n)+τ(n) for all positive integers n where τ(n) is the number of positive integer divisors of n. Determine whether two consecutive terms of this sequence can be perfect squares.
Original LaTeX notation
A sequence $(a_n)_{n=1}^{\infty}$ of positive integers satisfies the condition $a_{n+1} = a_n +\tau (n)$ for all positive integers $n$ where $\tau (n)$ is the number of positive integer divisors of $n$. Determine whether two consecutive terms of this sequence can be perfect squares.

Discussion

Discussion

No discussion posts on this page yet. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

Source and history

Official source

initial import