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Omni-MATH / Let n(≥2) be a positive integer. Find the minimum m, so that there exists x_(ij)(1≤i,j≤n) satisfying: (1)For every 1≤i,j≤n,x_(ij)=max{x_(i1),x_(i2),...,x_(ij)} or …
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problem
Let be a positive integer. Find the minimum , so that there exists satisfying:
(1)For every or
(2)For every , there are at most indices with
(3)For every , there are at most indices with
Plain-text mathematical notation (without MathML)
Let n(≥2) be a positive integer. Find the minimum m, so that there exists x_(ij)(1≤i,j≤n) satisfying:
(1)For every 1≤i,j≤n,x_(ij)=max{x_(i1),x_(i2),...,x_(ij)} or x_(ij)=max{x_(1j),x_(2j),...,x_(ij)}.
(2)For every 1≤i≤n, there are at most m indices k with x_(ik)=max{x_(i1),x_(i2),...,x_(ik)}.
(3)For every 1≤j≤n, there are at most m indices k with x_(kj)=max{x_(1j),x_(2j),...,x_(kj)}.Original LaTeX notation
Let $ n(\ge2) $ be a positive integer. Find the minimum $ m $, so that there exists $x_{ij}(1\le i ,j\le n)$ satisfying:
(1)For every $1\le i ,j\le n, x_{ij}=max\{x_{i1},x_{i2},...,x_{ij}\} $ or $ x_{ij}=max\{x_{1j},x_{2j},...,x_{ij}\}.$
(2)For every $1\le i \le n$, there are at most $m$ indices $k$ with $x_{ik}=max\{x_{i1},x_{i2},...,x_{ik}\}.$
(3)For every $1\le j \le n$, there are at most $m$ indices $k$ with $x_{kj}=max\{x_{1j},x_{2j},...,x_{kj}\}.$Discussion
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