benchmarks.wiki / Public workspace

Omni-MATH / For every positive integer n, let f(n), g(n) be the minimal positive integers such that 1+(1)/(1!)+(1)/(2!)+…+(1)/(n!)=(f(n))/(g(n)). Determine whether there exists a positive inte…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

problem

For every positive integer nn, let f(n)f(n), g(n)g(n) be the minimal positive integers such that 1+11!+12!+…+1n!=f(n)g(n).1+\frac{1}{1!}+\frac{1}{2!}+\dots +\frac{1}{n!}=\frac{f(n)}{g(n)}. Determine whether there exists a positive integer nn for which g(n)>n0.999ng(n)>n^{0.999n}.
Plain-text mathematical notation (without MathML)
For every positive integer n, let f(n), g(n) be the minimal positive integers such that
1+(1)/(1!)+(1)/(2!)+…+(1)/(n!)=(f(n))/(g(n)).
Determine whether there exists a positive integer n for which g(n)>n^(0.999n).
Original LaTeX notation
For every positive integer $n$, let $f(n)$, $g(n)$ be the minimal positive integers such that
\[1+\frac{1}{1!}+\frac{1}{2!}+\dots +\frac{1}{n!}=\frac{f(n)}{g(n)}.\]
Determine whether there exists a positive integer $n$ for which $g(n)>n^{0.999n}$.

Discussion

Discussion

No discussion posts on this page yet. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.

Source and history

Official source

initial import