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Omni-MATH / Let's put down a=−b, then we have that f(b²)=f(b)+f(−b)−f(b)f(−b). If we need that f would be nondecreasing, it must be held that f(b²)>=f(b), so f(−b)[1−f(b)]>=0 too. From that we… · Discussion

Discussing Let's put down a=−b, then we have that f(b²)=f(b)+f(−b)−f(b)f(−b). If we need that f would be nondecreasing, it must be held that f(b²)>=f(b), so f(−b)[1−f(b)]>=0 too. From that we… · Omni-MATH

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