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Omni-MATH / In a right angled-triangle ABC, ∠ACB=90^(o). Its incircle O meets BC, AC, AB at D,E,F respectively. AD cuts O at P. If ∠BPC=90^(o), prove AE+AP=PD. · Discussion
Discussing In a right angled-triangle ABC, ∠ACB=90^(o). Its incircle O meets BC, AC, AB at D,E,F respectively. AD cuts O at P. If ∠BPC=90^(o), prove AE+AP=PD. · Omni-MATH
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