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Omni-MATH / Triangle ABC obeys AB=2AC and ∠BAC=120^(∘). Points P and Q lie on segment BC such that beginaligned AB^2+BC cdot CP & =BC^2 3AC^2+2BC cdot CQ & =BC^2 endaligned Find … · Discussion

Discussing Triangle ABC obeys AB=2AC and ∠BAC=120^(∘). Points P and Q lie on segment BC such that begin{aligned} AB^{2}+BC cdot CP & =BC^{2} 3AC^{2}+2BC cdot CQ & =BC^{2} end{aligned} Find … · Omni-MATH

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