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MATH / Find the value of n that satisfies 2(n+1)!+6n!=3(n+1)!, where n!=n⋅(n−1)⋅(n−2)⋯2⋅1. · Discussion

Discussing Find the value of n that satisfies 2(n+1)!+6n!=3(n+1)!, where n!=n⋅(n−1)⋅(n−2)⋯2⋅1. · MATH

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