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Omni-MATH / Let b(x)=x²+x+1. The polynomial x²⁰¹⁵+x²⁰¹⁴+⋯+x+1 has a unique "base b(x) " representation x²⁰¹⁵+x²⁰¹⁴+⋯+x+1=∑_(k=0)^(N)a_(k)(x)b(x)^(k) where each "digit" a_(k)(x) is either the z… · Discussion

Discussing Let b(x)=x²+x+1. The polynomial x²⁰¹⁵+x²⁰¹⁴+⋯+x+1 has a unique "base b(x) " representation x²⁰¹⁵+x²⁰¹⁴+⋯+x+1=∑_(k=0)^(N)a_(k)(x)b(x)^(k) where each "digit" a_(k)(x) is either the z… · Omni-MATH

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