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Omni-MATH / Let a,b,c,x,y, and z be complex numbers such that a=(b+c)/(x−2), b=(c+a)/(y−2), c=(a+b)/(z−2). If xy+yz+zx=67 and x+y+z=2010, find the value of xyz. · Discussion

Discussing Let a,b,c,x,y, and z be complex numbers such that a=(b+c)/(x−2), b=(c+a)/(y−2), c=(a+b)/(z−2). If xy+yz+zx=67 and x+y+z=2010, find the value of xyz. · Omni-MATH

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