benchmarks.wiki

benchmarks.wiki / Public workspace

Omni-MATH / Find the value of (sin²B+sin²C−sin²A)/(sinBsinC) given that (sinB)/(sinC)=(AC)/(AB), (sinC)/(sinB)=(AB)/(AC), and (sinA)/(sinBsinC)=(BC)/(AC⋅AB). · Discussion

Discussing Find the value of (sin²B+sin²C−sin²A)/(sinBsinC) given that (sinB)/(sinC)=(AC)/(AB), (sinC)/(sinB)=(AB)/(AC), and (sinA)/(sinBsinC)=(BC)/(AC⋅AB). · Omni-MATH

Posts

Chronological order within this page.

Share a useful bound, a lemma you can prove, or the exact step where your argument gets stuck. Use the posting template.