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MATH / In rectangle ABCD with AB=16, P is a point on BC so that ∠APD=90^(∘). TS is perpendicular to BC with BP=PT, as shown. PD intersects TS at Q. Point R is on CD such that RA passes th… · Discussion

Discussing In rectangle ABCD with AB=16, P is a point on BC so that ∠APD=90^(∘). TS is perpendicular to BC with BP=PT, as shown. PD intersects TS at Q. Point R is on CD such that RA passes th… · MATH

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