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Omni-MATH / Point P lies inside equilateral triangle ABC so that ∠BPC=120^(∘) and AP√(2)=BP+CP. (AP)/(AB) can be written as (a√(b))/(c), where a,b,c are integers, c is positive, b is square-fr… · Discussion

Discussing Point P lies inside equilateral triangle ABC so that ∠BPC=120^(∘) and AP√(2)=BP+CP. (AP)/(AB) can be written as (a√(b))/(c), where a,b,c are integers, c is positive, b is square-fr… · Omni-MATH

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