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CRUXEval / sample_35 / B ", [" bBb ", " BaB ", " bB", " bBbB ", " bbb"]

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(pattern, items):
    result = []
    for text in items:
        pos = text.rfind(pattern)
        if pos >= 0:
            result.append(pos)

    return result

input

" B ", [" bBb ", " BaB ", " bB", " bBbB ", " bbb"]

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Source and history

upstream_id / Original problem ID: sample_35
task_id: 215c3d37-4505-527f-83cd-c793e25705e8
task_key: default--test--sample~5f35
task_revision_id: 2
config / split: default / test

Official source

initial import