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CRUXEval / sample_452 / 'l000*',

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text):
    counter = 0
    for char in text:
        if char.isalpha():
            counter += 1
    return counter

input

'l000*',

Discussion

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Source and history

upstream_id / Original problem ID
sample_452
task_id
21a80691-9c69-511a-b22f-ed622ab67beb
task_key
default--test--sample~5f452
task_revision_id
1
config / split
default / test

Official source

initial import