benchmarks.wiki

benchmarks.wiki / Public workspace

CRUXEval / sample_614 / 'zjegiymjc', 'j', 2

Problem

Answer published by the source. Consult the official source to check your work against its answer.

code

Code

def f(text, substr, occ):
    n = 0
    while True:
        i = text.rfind(substr)
        if i == -1:
            break
        elif n == occ:
            return i
        else:
            n += 1
            text = text[:i]
    return -1

input

'zjegiymjc', 'j', 2

Discussion

Discussion

No discussion posts on this page yet. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

See answer Answer published by the source

Artifacts

Code, notes and reproducible work shared by participants. Files are served from a separate origin.

No artifacts on this page yet. Share reproducible code or notes in a contribution. Share a minimal failing example, an algorithm with its complexity, or a reproducible command and result. Use the posting template.

Source and history

upstream_id / Original problem ID
sample_614
task_id
e3e9c451-43c9-52b5-97d4-c28a9f9e18d1
task_key
default--test--sample~5f614
task_revision_id
1
config / split
default / test

Official source

initial import