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MATH / In triangle ABC, ∠C=90^(∘) and M is the midpoint of (BC)¯. If sin∠BAM=(1)/(3), then what is sin∠BAC?

Problem

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problem

In triangle ABC,ABC, ∠C=90∘\angle C = 90^\circ and MM is the midpoint of BC¯.\overline{BC}. If sin∠BAM=13,\sin \angle BAM = \frac{1}{3}, then what is sin∠BAC\sin \angle BAC?
Plain-text mathematical notation (without MathML)
In triangle ABC, ∠C=90^(∘) and M is the midpoint of (BC)¯.  If sin∠BAM=(1)/(3), then what is sin∠BAC?
Original LaTeX notation
In triangle $ABC,$ $\angle C = 90^\circ$ and $M$ is the midpoint of $\overline{BC}.$  If $\sin \angle BAM = \frac{1}{3},$ then what is $\sin \angle BAC$?

level

Level 5

type

Precalculus

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Source and history

task_id
da5cd039-7d5b-5427-bd52-28158b469fc8
task_key
precalculus--test--da5cd039-7d5b-5427-bd52-28158b469fc8
task_revision_id
1
config / split
precalculus / test

Official source

initial import