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MMLU-Pro / 4588 / The isomer of C_2H_5OH(l) is CH_3 - O - CH_3(g) . Given that, at 25°C, the heat…

Problem

Answer published by the source. Consult the official source to check your work against its answer.

question

The isomer of C_2H_5OH(l) is CH_3 - O - CH_3(g) . Given that, at 25°C, the heat of formation of C_2H_5OH(l) = - 66 kcal/mole, the heat of combustion of the isomeric CH_3 - O - CH_3(g) to CO_2(g) and H_2O(l) = - 348 kcal/mole, the heat of formation of H_2O(l) = - 68 kcal/mole and the heat of combustion of carbon to CO_2(g) = - 94 kcal/mole. Calculate a) \DeltaH_298°K for the reaction and b) \DeltaE_298°K for the reaction assuming \DeltaH_298°K in part a) = - 10 kcal.

category

chemistry

options

  1. \DeltaH = 22 kcal, \DeltaE = - 10.6 kcal
  2. \DeltaH = 204 kcal, \DeltaE = - 204 kcal
  3. \DeltaH = 204 kcal, \DeltaE = 204 kcal
  4. \DeltaH = 348 kcal, \DeltaE = - 188 kcal
  5. \DeltaH = 66 kcal, \DeltaE = - 10 kcal
  6. \DeltaH = -66 kcal, \DeltaE = -10 kcal
  7. \DeltaH = 66 kcal, \DeltaE = 10 kcal
  8. \DeltaH = -22 kcal, \DeltaE = 10.6 kcal
  9. \DeltaH = -348 kcal, \DeltaE = 188 kcal
  10. \DeltaH = 348 kcal, \DeltaE = 10 kcal

src

stemez-PhysicalChemistry

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Source and history

upstream_id / Original problem ID
4588
task_id
face05c0-3c27-544a-9558-b4a1420ce677
task_key
default--test--4588
task_revision_id
1
config / split
default / test

Official source

initial import